Помогите решить лагорифм
(log₇(7*2) - 1\3(log₇(7*8) ) \ (log₆(6*5) - 1\2 (log₆(25*6) )= (log₇7 + log₇2 - 1\3 log₇ 7 - log₇∛ 8 ) \ ( log₆6 + log₆5 - log₆√25 -1\2log₆6) = (1+ log₇2- 1\3 - log₇2) \ (1+ log₆5 - log₆5 -1\2)= (1- 1\3) \ (1- 1\2) = 2\3 : 1\2 = 4\3 = 1 1\3