F(x)=(x²-5x)(x-4)=x³-9x²-20x f`(x)=3x²-18x-20
F'(x)=(x^2-5x)'(x-4)+(x^2-5x)(x-4)'=(2x-5)(x-4)+x^2-5x=2x^2-8x-5x+20+x^2-5x= =3x^2-18x+20