Решите уравнение (x^2-25)^2+(x^2+3x-10)^2=0

Question

Решите уравнение (x^2-25)^2+(x^2+3x-10)^2=0

Answer 1

X²-25=(x-5)(x+5)
x²+3x-10)=(x+5)(x-2)
x1+x2=-3 U x1*x2=-10⇒x1=-5 U x2=2

(x-5)(x+5)+(x+5)(x-2)=0
(x+5)(x-5+x-2)=0
(x+5)(2x-7)=0
x+5=0⇒x=-5
2x-7=0⇒2x=7⇒x=3,5