Реакция ионного обмена ZnCl2+NaOH H3PO4+KOH
1) ZnCl2+ 2NaOH= Zn(OH)2/+ 2 NaCl 2+ - + - + - Zn+ 2Cl+ 2Na+ 2OH= Zn(OH)2/+ 2Na+ 2Cl 2+ - Zn+2OH=Zn(OH)2 2) H3PO4+ 3KOH= K3PO4+3H2O + 2- + - + 2- 3H+ PO4+ 3K+3OH=3K+ PO4 +3H2O + - 3H+3OH=3H2O