. Решите уравнение пжлстx/12+x/6+x=-8(целых) 3/4

Решите задачу:

$\frac{x}{12} + \frac{x}{6} + x = - 8 \frac{3}{4}$
$\frac{x}{12} + \frac{x*2}{12} + x = - \frac{24}{4}$
$\frac{x}{12} + \frac{x*2}{12} +x =- \frac{72}{12}$
$\frac{x}{12} + \frac{x*2}{12} + \frac{x}{1} =- \frac{72}{12}$
$\frac{x+ 2x+x}{12} = - \frac{72}{12}$
$\frac{4x}{12} = - \frac{72}{12}$
$\frac{4x}{12} = - 6$
$4x = -6*12$
$4x = -72$
$x = - \frac{72}{4}$
$x = 18$