Решите уравнение:
7(1-sin^2 x) - 13sinx -13=0 -7sin^2 x -13sinx - 6 = 0 7sin^2 x +13sinx + 6 = 0 пусть sinx=t => sin^2 x => t^2 7t^2 + 13t +6 =0 D = 169 - 4*7*6= 1 t = (-13 +(-) 1 )/ 14 t1 = -1 t2= -6/7 1) sinx = -1 2) sinx = -6/7 x= - + 2 x=(-1)^k arcsin (-6/7) + x=(-1)^k+1 arcsin6/7 +