0 \\ \\ x_{1}= \frac{46- \sqrt{36} }{2*4}=5 \\ \\ x_{2}= \frac{46+ \sqrt{36} }{2*4}=6.5 \\ \\ y_{1} = 5-4=1 \\ \\ y_2=6.5-4=2.5 " alt=" \left \{ {{ \sqrt{x-y+5}=3} \atop { \sqrt{x+y-5}=11-2x }} \right. \\ \\ \left \{ {{x-y-5=9} \atop {x+y-5=121-44x+4 x^{2} }} \right. \\ \\ \left \{ {{x-y=4} \atop {x+y-5-121+44x-4 x^{2} =0}} \right. \\ \\ \left \{ {{y=x-4} \atop {4 x^{2} -45x-y+126=0}} \right. \\ \\ 4x^2-45x-x+4+126=0 \\ \\ 4x^2-46x+130=0 \\ \\ D=(-46)^2-4*4*130=36>0 \\ \\ x_{1}= \frac{46- \sqrt{36} }{2*4}=5 \\ \\ x_{2}= \frac{46+ \sqrt{36} }{2*4}=6.5 \\ \\ y_{1} = 5-4=1 \\ \\ y_2=6.5-4=2.5 " align="absmiddle" class="latex-formula">
Ответ: (5; 1) и (6,5: 2,5)