(3х^2+xy-y^2)-((2x^2+xy+3y^2)-(5x^2-y^2))=???

Question

(3х^2+xy-y^2)-((2x^2+xy+3y^2)-(5x^2-y^2))=???

Answer 1

= 6х+ху-2у-(2х+ ху+6 у- 10х+2 у)=6х + ху - 2х-ху-6у+10х-2у= 14х-8у