Найдите значение выражения 81 в степени 1/4 - (3√3)*2
Три корня из трёх в квадрате или умножить на 2?
81^1/4-(3√3)²=(3^4)^1/4 -(3√3)²=3-9*3=3-27=-24
![81^\frac{1}{4}-(3\sqrt3)\cdot2=\sqrt[4]{81}-6\sqrt3=\sqrt[4]{3^4}-6\sqrt3=3-6\sqrt3=3(1-2\sqrt3)](https://tex.z-dn.net/?f=81%5E%5Cfrac%7B1%7D%7B4%7D-%283%5Csqrt3%29%5Ccdot2%3D%5Csqrt%5B4%5D%7B81%7D-6%5Csqrt3%3D%5Csqrt%5B4%5D%7B3%5E4%7D-6%5Csqrt3%3D3-6%5Csqrt3%3D3%281-2%5Csqrt3%29 "81^\frac{1}{4}-(3\sqrt3)\cdot2=\sqrt[4]{81}-6\sqrt3=\sqrt[4]{3^4}-6\sqrt3=3-6\sqrt3=3(1-2\sqrt3)")
![81^\frac{1}{4}-(3\sqrt3)^2=\sqrt[4]{81}-3^2\cdot(\sqrt3)^2=\sqrt[4]{3^4}-9\cdot3=3-27=-24](https://tex.z-dn.net/?f=81%5E%5Cfrac%7B1%7D%7B4%7D-%283%5Csqrt3%29%5E2%3D%5Csqrt%5B4%5D%7B81%7D-3%5E2%5Ccdot%28%5Csqrt3%29%5E2%3D%5Csqrt%5B4%5D%7B3%5E4%7D-9%5Ccdot3%3D3-27%3D-24 "81^\frac{1}{4}-(3\sqrt3)^2=\sqrt[4]{81}-3^2\cdot(\sqrt3)^2=\sqrt[4]{3^4}-9\cdot3=3-27=-24")