Fe(OH)3 + NaOH => FeCl3 + K4[Fe(CN)6] => CuSO4 + K4[Fe(CN)6] => KMnO4 + H2SO4 +...

Question

Fe(OH)3 + NaOH =>

FeCl3 + K4[Fe(CN)6] => CuSO4 + K4[Fe(CN)6] =>

KMnO4 + H2SO4 + Na2SO3

Answer 1

Fe(OH)3 + NaOH --> (сплавление) NaFeO2 + 2H2O

FeCl3 + K4[Fe(CN)6] --> 3KCl + KFe[Fe(CN)6]

2CuSO4 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2K2SO4

2KMnO4 + 3H2SO4 + 5Na2SO3 = 2MnSO4 + K2SO4 + 5Na2SO4 + H2O

Mn(+7) +5e -> Mn(+2) | 2

S(+4) -2e -> S(+6)        | 5

2Mn(+7) + 5S(+4) -> 2Mn(+2) + 5S(+6)