Помогите пожалуйста решить.. вот это

Решите задачу:

$\cfrac{(6,25-2,8)\cdot \frac{20}{23}}{\frac{7}{16}\cdot(3\frac{5}{21}+1\frac{1}{3})}+0.5\cdot(6.1+\cfrac{2.1}{\frac{14}{15}+1.4})= \\\ =\cfrac{3,4\cdot\frac{20}{23}}{\frac{7}{16}\cdot(\frac{68}{21}+\frac{4}{3})}+0.5\cdot(6.1+ \cfrac{2.1}{\frac{28}{30}+ \frac{14}{10}})= \\\ =\cfrac{\frac{69}{23}}{\frac{7}{16}\cdot(\frac{68}{21}+\frac{28}{21})}+0.5\cdot(6.1+\cfrac{2.1}{ \frac{28}{30}+\frac{42}{30}})=$
$=\cfrac{3}{\frac{7}{16}\cdot\frac{96}{21}}+0.5\cdot(6.1+\cfrac{2.1}{ \frac{70}{30}})= \\\ =\cfrac{3}{\frac{7\cdot96}{16\cdot21}}+0.5\cdot(6.1+\cfrac{2.1\cdot3}{7})= \\\ =\cfrac{3}{2}+0.5\cdot(6.1+0.9)=1.5+0.5\cdot7=1.5+3.5=5$