0\; \to \; x^2-7x-8<0\\\\D=49+32=81\\\\x_1=\frac{7-9}{2}=-1,x_2=8\\\\x^2-7x-8=(x+1)(x-8) <0\\\\+ + + + + (-1)- - - -(8)+ + + + +\\\\x\in (-1,8)" alt="\frac{12}{x^2-7x-8} \leq 0,\quad ODZ:\; x^2-7x-8\ne 0,\; \to \; x\ne -1,x\ne 8\\\\12>0\; \to \; x^2-7x-8<0\\\\D=49+32=81\\\\x_1=\frac{7-9}{2}=-1,x_2=8\\\\x^2-7x-8=(x+1)(x-8) <0\\\\+ + + + + (-1)- - - -(8)+ + + + +\\\\x\in (-1,8)" align="absmiddle" class="latex-formula">