Pls: 2sin^2x+√3sinx = 0
2sinxcosx+coren3 sinx=0 sinx(2cosx+coren3)=0 sinx=0 ili 2cosx+coren3=0 x=pin cosx=-coren3)/2 x=+-(pi-pi/6)+2pin x=+-5pi/6+2pin