1)5-5cos²x+6cosx-6=0
5cos²x-6cosx+1=0
cosx=a
5a²-6a+1=0
D=36-20=16
a1=(6-4)/10=1/5⇒cosx=1/5⇒=x=+-arccos1/5+2πn
a2=(6+4)/10=1⇒cosx=1⇒x=2πn
3sin²x+sinxcosx-2cos²x=0 /cos²≠0
3tg²x+tgx-2=0
tgx=a
3a²+a-2=0
D=1+24=25
a1=(-1-5)/6=-1⇒tgx=-1⇒x=-π/4+πn
a²=(-1+5)/6=2/3⇒tgx=2/3⇒x=arctg2/3+πn