РЕШИТЕ ПОЖАЛУЙСТА x^{2} +7X+6=0 /. x^{2} +6 x +9=0 .x^{2}+3x-54=0 . x^{2} +11 x +24=0....

$x^{2}+7x+6=0 \\ d=7^{2}-4*1*6=25\\ x_{1}= \frac{-7+\sqrt{25}}{2}=-1,x_{2}=\frac{-7-\sqrt{25}}{2}=-6 \\ \\ x^{2}+6x+9=0 \\d=6^{2}-4*1*9=0\\ x_{1}= \frac{-6+\sqrt{0}}{2}=-3,x_{2}=\frac{-6-\sqrt{0}}{2}=-3 \\ \\ x^{2}+3x-54=0 \\ d=7^{2}-4*1*6=25\\ x_{1}= \frac{-7+\sqrt{25}}{2}=-1,x_{2}=\frac{-7-\sqrt{25}}{2}=-6$

$x^{2}+11x+24=0 \\ d=11^{2}-4*1*24=121-96=25\\ x_{1}= \frac{-11+\sqrt{25}}{2}=-3,x_{2}=\frac{-11-\sqrt{25}}{2}=-8 \\ \\ x^{2}+x-56=0 \\d=1^{2}-4*1*(-56)=1+224=225=15^{2}\\ x_{1}= \frac{-1+\sqrt{225}}{2}=7,x_{2}=\frac{-1-\sqrt{225}}{2}=-8 \\ \\ x^{2}-x-2=0 \\ d=(-1)^{2}-4*1*(-2)=9\\ x_{1}= \frac{1+\sqrt{9}}{2}=2,x_{2}=\frac{1-\sqrt{9}}{2}=-1$

$x^{2}-4x-5=0 \\ d=(-4)^{2}-4*1*(-5)=36\\ x_{1}= \frac{4+\sqrt{36}}{2}=5,x_{2}=\frac{4-\sqrt{36}}{2}=-1 \\ \\ x^{2}+8x+12=0 \\d=8^{2}-4*1*12=64-48=16\\ x_{1}= \frac{-8+\sqrt{16}}{2}=-2,x_{2}=\frac{-8-\sqrt{16}}{2}=-6 \\ \\ x^{2}+4x+7=0 \\ d=4^{2}-4*1*7=16-28<0$
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