Решите уравнение 20x-(2x+1)^2=4(x+2)-(2x-3)^2

Question

Решите уравнение 20x-(2x+1)^2=4(x+2)-(2x-3)^2

Comments

20х-4х^2+1=4x+8-4x^2-96x=2 x=0,3

Answer 1

20x-4x^2-1=4x+8-4x^2+9
20x-4x-4x^2+4x^2=8+9+1
16x=18
X=1,125

Answer 2

20х-4х^2+4х+1=4х+8-4х^2-12х+9
20х-4х^2+4х-4х+4х^2+12х=8-1+9
8х=16
х=16/8
х=2

Comments

ошибка...

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у всех?

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32х=16 x=0.5

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6х=-18 х=-3

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х=0.5