f(x)=(sin 2x -x√2)
f'(x)=(sin 2x -x√2)' = 2cos(2x) -
√2 = 0
2x = pi /4 + 2 pi k, 2x = -pi /4 + 2 pi k
x = pi / 8 + pi k, x = -pi /8 + pi k
так как x Є [0;4п], то x = pi /8, x = 9pi /8, x = 17pi /8, x = 25pi /8, x = 7pi /8, x = 15pi /8, x = 23pi /8, x = 31pi /8.