![image](https://tex.z-dn.net/?f=ODZ%3A8%2B5x%3E0+%5C%5C+5x%3E-8+%5C%5C+x%3E+-%5Cfrac%7B8%7D%7B5%7D+%5C%5C+7-5x%3E0+%5C%5C+5x%3C7+%5C%5C+x%3C+%5Cfrac%7B7%7D%7B5%7D+%5C%5C+%28-%5Cfrac%7B8%7D%7B5%7D+%3B+%5Cfrac%7B7%7D%7B5%7D%29+++%5C%5C+log_2%288%2B5x%29%3Dlog_2%287-5x%29%2B1+%5C%5C+log_2%288%2B5x%29%3Dlog_2%287-5x%29%2Blog_22+%5C%5C+log_2%288%2B5x%29%3Dlog_2%2814-10x%29+%5C%5C+8%2B5x%3D14-10x+%5C%5C+15x%3D6+%5C%5C+x%3D+%5Cfrac%7B6%7D%7B15%7D+)
0 \\ 5x>-8 \\ x> -\frac{8}{5} \\ 7-5x>0 \\ 5x<7 \\ x< \frac{7}{5} \\ (-\frac{8}{5} ; \frac{7}{5}) \\ log_2(8+5x)=log_2(7-5x)+1 \\ log_2(8+5x)=log_2(7-5x)+log_22 \\ log_2(8+5x)=log_2(14-10x) \\ 8+5x=14-10x \\ 15x=6 \\ x= \frac{6}{15} " alt="ODZ:8+5x>0 \\ 5x>-8 \\ x> -\frac{8}{5} \\ 7-5x>0 \\ 5x<7 \\ x< \frac{7}{5} \\ (-\frac{8}{5} ; \frac{7}{5}) \\ log_2(8+5x)=log_2(7-5x)+1 \\ log_2(8+5x)=log_2(7-5x)+log_22 \\ log_2(8+5x)=log_2(14-10x) \\ 8+5x=14-10x \\ 15x=6 \\ x= \frac{6}{15} " align="absmiddle" class="latex-formula">
Ответ x=6/15