x=y+2\\x^2-xy+y^2=7\end{cases}\\\\(y+2)^2-y(y+2)+y^2=7\\y^2+4y+4-y^2-2y+y^2=7\\y^2+2y-3=0\\y_1=-3\ ;y_2=1\\x_1=-1\ ;x_2=3\\\\OTBET:(-1;-3);(3;1)" alt="\begin{cases}x-y=2=>x=y+2\\x^2-xy+y^2=7\end{cases}\\\\(y+2)^2-y(y+2)+y^2=7\\y^2+4y+4-y^2-2y+y^2=7\\y^2+2y-3=0\\y_1=-3\ ;y_2=1\\x_1=-1\ ;x_2=3\\\\OTBET:(-1;-3);(3;1)" align="absmiddle" class="latex-formula">