Решить уравнения....помогите...) 1. sin2x=√2 cosx 2. sin2x+√2sinx=0
1) SIn2x = 2SinxCosx
Sin2x = √2Cosx
2SinxCosx - √2Cosx = 0
Cosx(2Sinx - √2) = 0
Cos x = 0 или Sinx = √2/2
x₁ = π/2 + πk, k∈Z
2) 2SinxCosx + √2Sinx = 0
Sinx(2Cosx + √2) = 0
Sinx = 0 или Cosx = -√2/2
x₁ = πk
x₂ = ±3π/4 + 2πk