q= \sqrt[3]{64} = \sqrt[3]{4^3} =4 \\ \\ b_3=b_1q^2 => b_1= \frac{b_3}{q^2} = \frac{-3}{16}=- \frac{3}{16} " alt="b_3=b_1q^2 \\ b_6=b_1q^5 \\ \\ \frac{b_6}{b_3}= \frac{b_1q^5}{b_1q^2} =q^3 \\ \\ q^3=\frac{-192}{-3} =64 => q= \sqrt[3]{64} = \sqrt[3]{4^3} =4 \\ \\ b_3=b_1q^2 => b_1= \frac{b_3}{q^2} = \frac{-3}{16}=- \frac{3}{16} " align="absmiddle" class="latex-formula">
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