Помогите решить систему уравнения)))

$\left \{ {{\log_2(x+y)+2\log_4(x-y)=3,} \atop {3^{2+\log_3(2x-y)}=45;}} \right. \left \{ {{\log_2(x+y)+\frac22\log_2(x-y)=3,} \atop {3^{2}\cdot3^{\log_3(2x-y)}=45;}} \right.\\ \left \{ {{\log_2(x+y)+\log_2(x-y)=3,} \atop {3^{\log_3^(2x-y)}=\frac{45}{9};}} \right. \ \left \{ {{\log_2(x+y)\cdot(x-y)=\log_22^3,} \atop {3^{\log_3(2x-y)}=5;}} \right.\\ \left \{ {{2^{\log_2(x+y)\cdot(x-y)}=2^{\log_22^3}} \atop {2x-y=5}} \right. \\$

0\ \ \ y>-x\\ x-y>0 \ \ y0\ \ \ y<2x\\ -x0 y>0;\\ D(f): \left \{ {{-x0} \atop {x>0}} \right. }} \right. " alt=" \left \{ {x^2-y^2=8} \atop {2x-y=5}} \right. D(f):\\ x+y>0\ \ \ y>-x\\ x-y>0 \ \ y0\ \ \ y<2x\\ -x0 y>0;\\ D(f): \left \{ {{-x0} \atop {x>0}} \right. }} \right. " align="absmiddle" class="latex-formula">\\>
$\left \{ {{x^2-y^2=8} \atop {2x-y=5}} \right. \ \\ y=2x-5;\\ x^2-(2x-5)^2=8;\\ x^2-4x^2+20x-25=8;\\ 3x^2-20x+33=0;\\ D=20^2-4\cdot3\cdot33=400-396=4=(\pm2)^2;\\ x_1=\frac{20-2}{6}=\frac{18}{6}=3;\ y_1=2\cdot3-5=6-5=1;\\ (x=3; y=1)\in D(f); \\ x_2=\frac{20+2}{6}=\frac{22}{6}=\frac{11}{3}=3\frac{2}{3};\\ y_2=2\cdot\frac{11}{3}-5=\frac{22}{3}-\frac{15}{3}=\frac{7}{3}=2\frac{1}{3};\\ (x=3\frac23; y=2\frac13)\in D(f)\\$
имеем два ответа
$x=3;\ \ \ \ \ y=1;\\ x=3\frac23;\ \ \ y=2\frac13;\\$