Решение уравнение:1) 4х²-1=02)9х²-100=03)25х²=494)100р²=15)64у=28096)841у²=121

1)4х²-1=0, 4х²=1, х²=0,25, $x_{1} =0,5, x_{2} =-0,5$
2) $9 x^{2} -100=0, 9 x^{2} =100, x^{2} = \frac{100}{9} , x_{1} = \frac{10}{3} =3 \frac{1}{3}, x_{2} = -\frac{10}{3} =-3 \frac{1}{3}$
3) $25 x^{2} =49, x^{2} = \frac{49}{25} , x_{1} = \frac{7}{5} =1 \frac{2}{5} , x_{2} =-\frac{7}{5} =-1 \frac{2}{5}$
4) $100p ^{2} =1, p ^{2}= \frac{1}{100} , p_{1} = \frac{1}{10}, p_{2} = -\frac{1}{10}$
5) $64 y^{2} =2809, y^{2}= \frac{2809}{64} , y_{1}= \frac{53}{8} =6 \frac{5}{8} , y_{2}= -\frac{53}{8} =-6 \frac{5}{8}$
6) $841 y^{2} =121, y^{2} = \frac{121}{841}, y_{1} = \frac{11}{29}, y_{2} = -\frac{11}{29}$