б)(3,6*2целых7/9+1,125+5целых2/5*2целых7/9-1целая1/8):2,5

б) $(3,6\cdot2\frac{7}{9}+1,125+5\frac{2}{5}\cdot2\frac{7}{9}-1\frac{1}{8}):2,5=10$

1) $3,6\cdot2\frac{7}{9}=3\frac{6}{10}\cdot2\frac{7}{9}=3\frac{3}{5}\cdot\frac{25}{9}=\frac{18}{5}\cdot\frac{25}{9}=10$

2) $5\frac{2}{5}\cdot2\frac{7}{9}=\frac{27}{5}\cdot\frac{25}{9}=15$

3) $10+1,125=11,125$

4) $11,125+15=26,125$

5) $26,125-1\frac{1}{8}=26,125-1,125=25$

6) $25:2,5=10$