Log5(1-2x^2)=log5(1-6x)

Question

Log5(1-2x^2)=log5(1-6x)

Answer 1

0\\ 1-6x>0\\\\ 1-2x^2=1-6x\\ -2x(x-3)=0\\ x=0\\ x=3" alt="log_{5}(1-2x^2)=log_{5}(1-6x)\\ 1-2x^2>0\\ 1-6x>0\\\\ 1-2x^2=1-6x\\ -2x(x-3)=0\\ x=0\\ x=3" align="absmiddle" class="latex-formula">
учитывая ОДЗ , ответ 0