Cos2x-0.25=cos^2x помогите пожалуйста
cos2x-0.25=cos²x
cos²х - sin²x - 0.25 = cos²x
sin²x = - 0.25
1) sinx = - 0.5
x₁ = (-1)^(k + 1) · π/6 + πk
2) sinx = 0.5
x₂ = (-1)^k · π/6 + πk
cos 2x= cos^2x-sin^2x
cos^2x-sin^2x-cos^2x=0.25
sin^2x=-1/4
sin x=1/2
sin x=-1/2