помогите!!! срочно надо!!!!)))
3. sqrt(log2(2x^2)*log2(16x)/log2(4))=sqrt(1/2(1+log2(x^2))(4+log2(x));
(1+2log2(x))(4+log2(x))=9/4log2(x)
log2(x)=t
2(2t^2+9t+4)=9t^2
5t^2-18t-8=0
t1=4
t2=-2/5
log2(x)=4 x=16
log2(x)=-0,4 x=1/2^(0.4)
(1+2t)>0
(1+t)>0