Докажите тождество:(4а+1)²(4a-1)²=(16a²+1)-64a²

Question

Докажите тождество:
(4а+1)²(4a-1)²=(16a²+1)-64a²

Answer 1

(4а+1)²(4a-1)²=(16a²+1)-64a²
[(4a+1)(4a-1)]²=(16a²-1)²=(16a²)²-32a²+1-32a²+32a²=(16a²+1)²-64a²