помогите решить уравнение!
(√3 · ctgπx - 1)·(arccos(x/3)² - π/3) = 0
1) √3 · ctgπx - 1 = 0
ctgπx= 1/√3
πx = π/3 + πn
x₁ = 1/3 + n, n∈Z
2) arccos(x/3)²- π/3 = 0
arccos(x/3)² = π/3
x²/9 = cos π/3
x²/9= 1/2
x² = 9/2
x₂ = 1.5√3