(х+3)^4-13(х+3)^2+26

Question

(х+3)^4-13(х+3)^2+26

Answer 1

(х+3)²=a a²-13a+26=0 D=(-13)²-4*1*26=169-104=65=√65=8,062 a1=(-(-13)+8,062)/2*1=21,062/2 a1=10,531 a2=(-(-13)-8,062)/2=4,938/2 a2=2,469 (x+3)²=a1=10,531 x1+3=√10,531=3,245 x1=3,245-3 x1=0,245 (x2+3)²=a2=2,469 x2+3=1,571 x2=1,571-3 x2=-1,429