Решите уравнение x^2-10=-3x
x^2-10=-3x
x2 + 3x - 10 = 0 D = b2 - 4ac D = 9 + 40 = 49 = 7^2
x1,2 = -b ± √D/2a x1 = -3 + 7/2 = 4/2 = 2 x2 = -3 - 7/2 = - 10/2 = -5 Ответ: x1 = 2; x2 = -5
х^2-10=-3x х^2+3x-10=0 Д=9 - 4*(-10)=49=7^2 х1=(-3+7)/2=4/2=2 x2=(-3-7)/2=-10/2=-5