0, 4x>-1, x>-\frac{1}{4}\\\\log_{\frac{1}{7}}(4x+1)49\\\\4x>48|:4\\\\x>12\\\\x \in (12;+\infty)" alt="log_{\frac{1}{7}}(4x+1)<-2|4x+1>0, 4x>-1, x>-\frac{1}{4}\\\\log_{\frac{1}{7}}(4x+1)49\\\\4x>48|:4\\\\x>12\\\\x \in (12;+\infty)" align="absmiddle" class="latex-formula">