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Ответ:

$4x^2-5x+1=0\\D=b^2-4ac=(-5)^2- 4*4*1 = 25 - 16 = 9\\x_1=\frac{5-\sqrt{9} }{2a} =\frac{5-3}{8} =\frac{2}{8} =0,25\\x_2=\frac{5+\sqrt{9} }{2a} =\frac{5+3}{8} =\frac{8}{8} =1\\answer: x_1=0,25; x_2=1$

$3x^2+2x-5=0\\D = b^2 - 4ac = 2^2 - 4*3*(-5) = 4 + 60 = 64\\x_1=\frac{-2-\sqrt{64} }{2a} =\frac{-2-8}{6} =\frac{-10}{6} =-\frac{5}{3} =1\frac{2}{3} \\x_2=\frac{-2+\sqrt{64} }{2a} =\frac{-2+8}{6} =\frac{6}{6} =1\\answer: x_1=1\frac{2}{3}; x_2=1$

$x^2-7x+10=0\\D = b^2 - 4ac = (-7)^2- 4*1*10 = 49 - 40 = 9\\x_1=\frac{7-\sqrt{9} }{2a} =\frac{7-3}{2} =\frac{4}{2} =2\\x_2=\frac{7+\sqrt{9} }{2a} =\frac{7+3}{2} =\frac{10}{2} =5\\answer: x_1=2; x_2=5\\$

$x^2+3x+2=0\\D = b^2 - 4ac = 3^2 - 4*1*2 = 9 - 8 = 1\\x_1=\frac{-3-\sqrt{1} }{2a} =\frac{-3-1}{2} =\frac{-4}{2} =-2\\x_2=\frac{-3+\sqrt{1} }{2a} =\frac{-3+1}{2} =\frac{-2}{2} =-1\\answer: x_1=-2; x_2=-1$