Расчитать относительные молекулярные массы веществ и массовые доли элементов в них если формулы этих веществ:HBr,K2CO3,Mg(OH)2,P2O5,FeCl3,Cu(NO3)2
W=m(в-ва)\m(р-ра) 1. M(HBr) = 1+80 = 81 w(H) = 1\81 = 0.01253*100% = 1.23% w(Br) = 100%-1.23% = 98.77% 2. M(K₂CO₃) = 2*40+16*3+12 = 140 w(K₂) = 80\140 = 0.57*100%= 57% w(C) = 12\140 = 0.086*100% = 8.6% w(O₃) = 100%-57%-8.6% = 34.4% 3. M(Mg(OH)₂) = 24+16*2+1*2 = 58 w(Mg) = 24\58 = 0.414*100% = 41.4% w(O) = 32\58 = 0.552*100% = 55.2%0 w(H) = 100%-41.4%-52.2% = 6.4% 4. M(P₂O₅) = 31*2+16*5 = 142 w(P₂) = 62\142 = 0.423*100% = 42.3% w(O₅) = 100%-42.3% = 57.7% 5. M(FeCl₃) = 56+35.5*3 = 162.5 w(Fe) = 56\162,5 = 0.345*100% = 34.5% w(Cl₃) = 100%-34.5% = 65.5% 6. M(Cu(NO₃)₂) = 64+28+96 = 188 w(Cu) = 64\188 = 0.34*100% = 34% w(N) = 28\188 = 0.15*100% = 15% w(O₃) = 100%-34%-15% = 51%