Помогите пожалуйста срочно.

$\frac{x^2+2x-15}{x-3} = 0,~~x\neq 3\\\frac{x^2+5x-3x-15}{x-3} = 0\\\frac{x(x+5)-3(x-3)}{x-3} = 0\\\frac{(x+5)(x-3)}{x-3} = 0\\x+5=0\\x=-5$

$\frac{x}{x+15}=\frac{1}{x},~~x\neq -12,~~x\neq 0\\x^2=x+12\\x^2-x-12=0\\x^2+3x-4x-12=0\\x(x+3)-4(x+3)=0\\(x+3)(x-4)=0\\x+3=0\\x-4=0\\x_1=-3\\x_2=4$

$\frac{6}{x}+\frac{6}{x+1}=5,~~x\neq -1, ~~x\neq 0\\\frac{6}{x}+\frac{6}{x+1}-5=0\\\frac{6(x+1)+6x-5x(x+1)}{x(x+1)}=0\\\frac{6x+6+6x-5x^2-5x}{x(x+1)}=0\\\frac{7x+6-5x^2}{x(x+1)}=0\\7x+6-5x^2=0\\5x^2-7x-6=0\\(5x+3)(x-2)=0\\5x+3=0\\x-2=0\\x_1=-\frac{3}{5}\\x_2=2$

$\frac{x}{x-2}-\frac{7}{x+2}=\frac{8}{x^2-4},~~x\neq 2, ~~x\neq-2\\\frac{x}{x-2}-\frac{7}{x+2}-\frac{8}{(x-2)(x+2)}=0\\\frac{x(x+2)-7(x-2)-8}{(x-2)(x+2)}=0\\\frac{x^2+2x-7x+14-8}{(x-2)(x+2)}=0\\\frac{x^2-5x+6}{(x-2)(x+2)}=0\\\frac{x^2-2x-3x+6}{(x-2)(x+2)}=0\\\frac{x(x-2)-3(x-3)}{(x-2)(x+2)}=0\\\frac{(x-2)(x-3)}{(x-2)(x+2)}=0\\\frac{x-3}{x+2}=0\\x-3=0\\x=3$