Ответ:
\left \{ {{(2+y)^{2}+y^{2} =4} \atop {x=2+y}} \right. =>\left \{ {{4+4y+2y^{2} =4} \atop {x=2+y}} \right. =>\left \{ {{2y^{2}+4y =4-4} \atop {x=2+y}} \right.=>\left \{ {{2y(y+2)=0} \atop {x=2+y}} \right. =>\left \ => \left \{ \left \{ {{2y=0} \atop {x=2+y}} \right. \atop \left \{ {{y+2=0} \atop {x=2+y}} \right. \right. => \left \{ \left \{ {{y=0} \atop {x=2}} \right. \atop \left \{ {{y=-2} \atop {x=0}} \right. } \right." alt="\left \{ {{x^{2}+y^{2} =4} \atop {x-y=2}} \right.=>\left \{ {{(2+y)^{2}+y^{2} =4} \atop {x=2+y}} \right. =>\left \{ {{4+4y+2y^{2} =4} \atop {x=2+y}} \right. =>\left \{ {{2y^{2}+4y =4-4} \atop {x=2+y}} \right.=>\left \{ {{2y(y+2)=0} \atop {x=2+y}} \right. =>\left \ => \left \{ \left \{ {{2y=0} \atop {x=2+y}} \right. \atop \left \{ {{y+2=0} \atop {x=2+y}} \right. \right. => \left \{ \left \{ {{y=0} \atop {x=2}} \right. \atop \left \{ {{y=-2} \atop {x=0}} \right. } \right." align="absmiddle" class="latex-formula">
Ответ: (2;0) и (04-2)
Объяснение: