СРОЧНО!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Решите задачу:

$a)\; \; f(z)=\dfrac{8}{(5z+4)^5}\\\\\\F(z)=\dfrac{1}{5}\int \dfrac{8\cdot 5\, dz}{(5z+4)^5}=\dfrac{8}{5}\int \dfrac{d(5z+4)}{(5z+4)^5}=\dfrac{8}{5}\cdot \dfrac{(5z+4)^{-4}}{-4}+C=-\dfrac{2}{5}\cdot \dfrac{1}{(5z+4)^{4}}+C$

$b)\; \; f(x)=\dfrac{-3}{sin^2(2x-3)}+\dfrac{1}{3}\\\\\\F(x)=\int \Big(\dfrac{-3}{sin^2(2x-3)}+\dfrac{1}{3}\Big)\, dx=-\dfrac{3}{2}\int \dfrac{d(2x-3)}{sin^2(2x-3)}+\dfrac{x}{3}=\\\\\\=\dfrac{3}{2}\cdot ctg(2x-3)+\dfrac{x}{3}+C$