Розвяжить неривности а) 3(х-2)+4(х+2)>6(х-2)+13 б)-х2-2х+3>-0​

Question

Розвяжить неривности а) 3(х-2)+4(х+2)>6(х-2)+13 б)-х2-2х+3>-0​

Answer 1

Ответ:

ответ во вложении.....

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Answer 2

6(x - 2) + 13" alt="3(x - 2) + 4(x + 2) > 6(x - 2) + 13" align="absmiddle" class="latex-formula">

6x - 12 + 13" alt="3x - 6 + 4x + 8> 6x - 12 + 13" align="absmiddle" class="latex-formula">

6x + 1" alt="7x + 2 > 6x + 1" align="absmiddle" class="latex-formula">

1 - 2" alt="7x - 6x > 1 - 2" align="absmiddle" class="latex-formula">

- 1" alt="x > - 1" align="absmiddle" class="latex-formula">

___________

- 0" alt=" - x2 - 2x + 3 > - 0" align="absmiddle" class="latex-formula">

0" alt=" - 2x - 2x + 3 > 0" align="absmiddle" class="latex-formula">

0" alt=" - 4x + 3 > 0" align="absmiddle" class="latex-formula">

- 3" alt=" - 4x > - 3" align="absmiddle" class="latex-formula">