Ответ:
Объяснение:
m = \frac{20+0,2d}{0,3} = \frac{200 + 2d}{3} \\0.3d = 8 + 0,2m; 3d = 80 + 2m\\3d = 80 + \frac{2}{3} (200 + 2d)\\9d = 240 + 2(200 + 2d) = 240 + 400 + 4d\\5d = 640 => d = 128 => m = \frac{200 + 2 * 128}{3} = 152" alt="0.3m = 20 + 0,2 d=>m = \frac{20+0,2d}{0,3} = \frac{200 + 2d}{3} \\0.3d = 8 + 0,2m; 3d = 80 + 2m\\3d = 80 + \frac{2}{3} (200 + 2d)\\9d = 240 + 2(200 + 2d) = 240 + 400 + 4d\\5d = 640 => d = 128 => m = \frac{200 + 2 * 128}{3} = 152" align="absmiddle" class="latex-formula">