Ответ:
[tex] \frac{2}{5} [/tex]
Объяснение:
[tex](8x - 3)(2x + 1) = (4x - 1) {}^{2} \\ 16x {}^{2} + 8x - 6x - 3 = 16x {}^{2} - 8x + 1 \\ 8x - 6x - 3 = - 8x + 1 \\ 2x - 3 = - 8x + 1 \\ 2x + 8x = 1 + 3 \\ 10x = 4 \\ x = \frac{4}{10} \\ x = \frac{2}{5} [/tex]