Ответ: 1. а) (x+5)*(x-6)
b) (2y+3)*(2y-1)
2. a) x1= -2, x=2
b) x1=0, x2=2
в) x1= -3, x2=4
г) x1= -5, x2= -1
3. a) 4x-3/x-1
b) x+2/x+4
Объяснение:
1.a) x^2+5x-6x-30
x*(x+5)-6(x+5)
1.b) 4y^2+6y-2y-3
2y*(2y+3)-(2y+3)
2. a) t^2+5t-36=0
t= -9
t=4
x^2= -9
x^=-4
x= -2
x=2
2.b) x^2/3-x = 2x/3-x, x≠3
x^2=2x
x^-2x=0
x*(x-2)=0
x*(x-2)=0
x=0
x-2=0
x=0
x=2, ≠3
2.в) 3x-9/x-1 + x+6/x+1 =3, x≠1, x≠ -1
3x-9/x-1 + x+6/x+1 -3 =0
=0
=0
=0
-12+x^2 -x=0
-x-12+x^2 =0
3x-4x-12+x^2=0
x*(x+3)-4(x+3)=0
(x+3)*(x-4)=0
x+3=0
x-4=0
x=-3
x=4
г) t^2 -3t-4=0
t= -1
t=4
(x+3)^2 = -1
(x+3)^2=4
x= -5
x= -1
3.a) 


3.b) 
