Ответ:
дано
m(ppa HCL) = 100 g
w(HCL) =15%
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m(Al)-?
m(HCL) = 100 * 15% / 100% = 15 g
2Al+6HCL-->2AlCL3+3H2
M(HCL) = 36.5 g/mol
n(HCL) = m/M = 15 / 36,5 = 0.41 mol
2n(AL) = 6n(HCL)
n(Al) = 2*0.41 / 6= 0.14 mol
M(Al) = 27 g/mol
m(Al) = n*M = 0.14 * 27 = 3.78 g
ответ 3.78 г
Объяснение: