Ответ:
Объяснение:
\left \{ {{\frac{x}{6}+\frac{y}{6}-\frac{x}{12}-\frac{y}{6}=0} \atop {y=6(2-\frac{x}{6})}} \right. <=> \left \{ {{\frac{x}{6}-\frac{x}{12}=0} \atop {y=12-x}} \right. <=> \left \{ {{\frac{2x}{12}-\frac{x}{12}=0} \atop {y=12-x}} \right. <=> \left \{ {{\frac{x}{12}=0} \atop {y=12-x}} \right. <=>\left \{ {{x=0} \atop {y=12-0}} \right. <=> \left \{ {{x=0} \atop {y=12}} \right." alt="\left \{ {{\frac{x}{6}+\frac{y}{6} =2} \atop {\frac{x}{12}+\frac{y}{6}=2}} \right. <=> \left \{ {{\frac{x}{6}+\frac{y}{6}-\frac{x}{12}-\frac{y}{6}=0} \atop {y=6(2-\frac{x}{6})}} \right. <=> \left \{ {{\frac{x}{6}-\frac{x}{12}=0} \atop {y=12-x}} \right. <=> \left \{ {{\frac{2x}{12}-\frac{x}{12}=0} \atop {y=12-x}} \right. <=> \left \{ {{\frac{x}{12}=0} \atop {y=12-x}} \right. <=>\left \{ {{x=0} \atop {y=12-0}} \right. <=> \left \{ {{x=0} \atop {y=12}} \right." align="absmiddle" class="latex-formula">