Ответ:
дано
m(ppa HCL) = 109.5 g
W(HCL) = 20%
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m(Cu(OH)2) -?
m(HCL) = 109.5 * 20% / 100% = 21.9 g
Cu(OH)2+2HCL-->CuCL2+2H2O
M(HCL) = 36.5 g/mol
n(HCL) = m/M = 21.9 / 36.5 = 0.6 mol
n(Cu(OH)2) = 2n(HCL)
n(Cu(OH)2) = 0.6 / 2 = 0.3 mol
M(Cu(OH)2) = 98 /mol
m(Cu(OH)2) = n*M = 0.3 * 98 = 29.4 g
ответ 29.4 г
Объяснение: