Ответ:
а) x=±π/6+2πk, k∈Z б) x=-π/3+2πk, x=4π/3+2πk, k∈Z
в) x=π/4+πk, k∈Z г) x=π/6+πk, k∈Z д) x=±π/6+2πk, k∈Z е) x=π/8+πk/2, k∈Z
Пошаговое объяснение:
а) cosx=1/2
x=±π/6+2πk, k∈Z
б) sinx=-√3/2
x=-π/3+2πk, k∈Z
x=π+π/3+2πk=4π/3+2πk, k∈Z
в) tgx=1
x=π/4+πk, k∈Z
г) cos(x+π/3)=0
x+π/3=π/2+πk
x=π/2-π/3+πk
x=π/6+πk, k∈Z
д)2cosx=1
cosx=1/2
x=±π/6+2πk, k∈Z
е) sin4x=1
4x=π/2+2πk
x=π/8+πk/2, k∈Z