Реши уравнение: 5t2+15t−(t+3)=0. Корни уравнения t1= ;t2=

$\displaystyle \sf 5t^2+15t-(t+3)=0\\\displaystyle \sf 5t^2+15t-t-3=0\\\displaystyle \sf 5t^2+14t-3=0\\\displaystyle \sf 5t^2+15t-t-3=0\\\displaystyle \sf 5t(t+3)-(t+3)=0\\\displaystyle \sf (t+3)(5t-1)=0\\\displaystyle \sf t+3=0\\\displaystyle \sf \bold{t_1=-3}\\\displaystyle \sf 5t-1=0\\\displaystyle \sf 5t=1\\\displaystyle \sf \bold{t_2=\frac{1}{5}}$

Корни уравнения

$\displaystyle \sf t_1=\boxed{\displaystyle \sf -3}$

$\displaystyle \sf t_2=\frac{\boxed{1}}{\boxed{\displaystyle \sf 5}}$