решить уравнение ctg 2х+4=0 cos3х= -1/2
Ctg2x+4=0 2x+4=arcctg0+Pn 2x+4=p/2+pn 2x=p/2-4+pn x=p/4-2+pn cos3x=-1/2 3x=+-arccos-1/2+2pn 3x=+-p-arccos1/2+2pn 3x=+-2p/3+2pn x=+-2p/6+2pn/3 x=+-p/3+2pn/3