1. log7 (x-4) = 1 + log7 (x-10)2. log2 (x^2 - 4x + 4) = 4

Question

1. log7 (x-4) = 1 + log7 (x-10)
2. log2 (x^2 - 4x + 4) = 4

Answer 1

                           Решение:

1.log7(x-4)=log7(7)+log(x-10)
x-4=7(x-10)
x-4=7x-70
70-4=6x
66=6x
x=11
2. x^2-4x+4=16
x^2-4x-12=0
x=2+-sqrt(4+12)=2+-4
x1=6
x2=-2