3(0,4y+3)-0,6=8 Допоможіть будьласка...

Решите задачу:

$1.2y + 9 - 0.6 = 8 \\ 1.2y = 8 - 9 + 0.6 \\ 1.2y = - 0.4 \\ y = - 0.4 \div 1.2 \\ y = - \frac{4}{10} \times \frac{10}{12} \\ y = - \frac{1}{3} \\ 2)0.6 \times (0.5x + \frac{2}{3}) = 2.25 + 5.3x \\ 0.3x + \frac{6}{10} \times \frac{2}{3} = 2.25 + 5.3x \\ 0.3x + 0.4 = 2.25 + 5.3x \\ 0.3x - 5.3x = 2.25 - 0.4 \\ - 5x = 1.85 \\ x = 1.85 \div ( - 5) \\ x = - 0.37$