Помогите решить биквадратное уравнение!ПОЖАЛУЙСТА!Дам 55 баллов

1) 2)

$x^2=t\\t^2-7t+12=0\\t_1=4\\t_2=3\\x^2=4\\x_1=2\\x_2=-2\\x^2=3\\x_3=\sqrt{3}\\x_4=-\sqrt{3}$ $x^2=t\\9t^2+5t-4=0\\t_1=-1\\t_2=\frac{4}{9}\\x^2=-1\\HET \ PEIIIENIY\\x^2=\frac{4}{9}\\x_1=\frac{2}{3}\\x_2=-\frac{2}{3}$

$-4z^4+1=0\\-4z^4=-1\\4z^4=1\\z^4=\frac{1}{4}\\z^2=t\\t^2=\frac{1}{4}\\\t_1=\frac{1}{2}\\t_2=-\frac{1}{2}\\z^2=-\frac{1}{2}\\HET\\z^2=\frac{1}{2}\\z_1=\frac{1}{\sqrt2}\\z_2=-\frac{1}{\sqrt2}$

4) Умножим на 10

$y^4-16y^2=-0\\y^2(y^2-16)=\\y_1=0\\y_2=-4\\y_3=-4$

$(x-1)^4-5(x-1)^2+4=0\\(x-1)^2=t\\t^2-5x+4=0\\t_1=1\\t_2=4\\(x-1)^2=x^2-2x+1\\x^2-2x+1=1\\x^2-2x=0\\x(x-2)=0\\x_1=0\\x_2=2\\x^2-2x+1=4\\x^2-2x-3=0\\x_3=3\\x_4=-1$